Chemistry - Surface Chemistry Question with Solution | TestHub

ChemistrySurface ChemistryAdsortionMedium2 minQB

ChemistryMediumsingle choice

The adsorption of a gas obeys Freundlich's isotherm and has following graph. Find the amount (in gm) of gas adsorbed per gm of adsorbent when pressure is 0.3 atm

Options:

Answer:

Solution:

Freundlich equation:

$lo g \frac{x}{m} = lo g k + \frac{1}{n} lo g P$

From the graph, slope $= tan 45° = 1$ , so $\frac{1}{n} = 1$ .

At $P = 0$

, intercept

lo g k = 0.3010

k = an t i lo g (0.3010) = 2

For

P = 0.3 a t m

$\frac{x}{m} = k P = 2 \times 0.3 = 0.6 g g^{- 1}$

Answer: (C) 0.6 g per g of adsorbent

Stream:JEESubject:ChemistryTopic:Surface ChemistrySubtopic:Adsortion

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