Chemistry - Surface Chemistry Question with Solution | TestHub

ChemistrySurface ChemistryGeneralEasy2 minPYQ_2020

ChemistryEasysingle choice

The flocculating power of the given ions for the specified colloidal sols will be such that

Options:

Arsenic sulphoid sol	Ferric hydroxide sol
${[F e {(C N)}_{6}]}^{4 -} > P O_{4}^{3 -} > S O_{4}^{2 -} > C l^{-}$	$A l^{3 +} > B a^{2 +} > N a^{+}$

Arsenic sulphoid sol	Ferric hydroxide sol
$A l^{3 +} > B a^{2 +} > N a^{+}$	${[F e {(C N)}_{6}]}^{4 -} > P O_{4}^{3 -} > S O_{4}^{2 -} > C l^{-}$

Arsenic sulphoid sol	Ferric hydroxide sol
$N a^{+} > B a^{2 +} > A l^{3 +}$	$C l^{-} > S O_{4}^{2 -} > P O_{4}^{3 -} > {[F e {(C N)}_{6}]}^{4 -}$

Arsenic sulphoid sol	Ferric hydroxide sol
$C l^{-} > S O_{4}^{2 -} > P O_{4}^{3 -} > {[F e {(C N)}_{6}]}^{4 -}$	$N a^{+} > B a^{2 +} > A l^{3 +}$

Answer:

Solution:

Coagulation power depends on nature of charge and amount of charge
Coagulation power $\propto$ charge on ion of electrolyte
As Arsenic sulphoid sol is negatively charged so for it cations will cause precipitation of ions and the order is $A l^{3 +} > B a^{2 +} > N a^{+}$
As Ferric hydroxide sol is positively charged so for it anions will cause precipitation of ions and the order is ${[F e {(C N)}_{6}]}^{4 -} > P O_{4}^{3 -} > S O_{4}^{2 -} > C l^{-}$

Stream:NTA_ABHYASSubject:ChemistryTopic:Surface ChemistrySubtopic:General

⏱ 2mℹ️ Source: PYQ_2020

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