Plot of log x/m against log p is a straight line inclined at an angle of 45 ° . When the pressure is 0.5 atm and Freundlich parameter, k is 10, the amount of soluble adsorbed per gram of adsorbent wil

Question

Plot of log x/m against log p is a straight line inclined at an angle of 45 ° . When the pressure is 0.5 atm and Freundlich parameter, k is 10, the amount of soluble adsorbed per gram of adsorbent will be (log 5 = 0.6990)

TestHub · Accepted Answer

According to Freundlich equation x m = k p 1 n log ⁡ x m = log ⁡ k + 1 n log ⁡ p So plot of log x/m vs log p is linear wit slope = 1/n and intercept = log k. Thus 1 n = tan ⁡ θ = tan ⁡ 4 5 ° = 1 or n = 1 At p = 0.5 atm and k = 10 x m = 10 × ( 0.5 ) 1 = 5 so x = 5 g

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