Chemistry - Stoichiometry Question with Solution | TestHub
ChemistryStoichiometryProblems Based on Mixtures, Percentage PurityMedium2 minQB
ChemistryMediumsingle choice
Passage / Comprehension
{"root":{"type":"root","format":"","indent":0,"version":1,"children":[{"type":"paragraph","format":"","indent":0,"version":1,"children":[{"mode":"normal","text":"Two grams of a moist sample of a mixture of sodium chloride and sodium chlorate was dissolved in water and made up to 250 ml. Twenty-five millilitres of this solution was treated with ","type":"text","style":"","detail":0,"format":0,"version":1},{"type":"equation","format":"latex","inline":true,"version":1,"equation":"\\mathrm{SO_{2}}"},{"mode":"normal","text":" to reduce the chlorate to chloride and excess ","type":"text","style":"","detail":0,"format":0,"version":1},{"type":"equation","format":"latex","inline":true,"version":1,"equation":"\\mathrm{SO_{2}}"},{"mode":"normal","text":" was removed by boiling. The total chloride was precipitated as silver chloride. The weight of the precipitate was 0.3444 g. In another experiment, 25 ml of the original solution was heated with 40 ml of 0.2 N solution of ferrous sulphate and unreacted ferrous sulphate required 10 ml of 0.08 N solution of an oxidizing agent for complete oxidation. (Na = 23, Ag = 108, Cl = 35.5)","type":"text","style":"","detail":0,"format":0,"version":1}],"direction":"ltr","textFormat":0}],"direction":"ltr"}}
What is the mass per cent of moisture present in the moist sample?
Options:
Answer:
C
Solution:
Mass of = 12 mmol × 106.5 = 1278 mg; mass of = 12 mmol × 58.5 = 702 mg; total salts = 1980 mg in the 2 g sample. Moisture = 2000 - 1980 = 20 mg, i.e. 1.0%, matching (c).
Stream:JEESubject:ChemistryTopic:StoichiometrySubtopic:Problems Based on Mixtures, Percentage Purity
⏱ 2mℹ️ Source: QB
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