Hydrogen peroxide in aqueous solution decomposes on warming to give oxygen according to the equation
$2 H_{2} O_{2} (aq) \to 2 H_{2} O (ℓ) + O_{2} (g)$
Under conditions where 1 mole of gas occupies $24 dm^{3} .100 cm^{3}$ of XM solution of $H_{2} O_{2}$ produces $3 dm^{3}$ of $O_{2}$ . Thus X is :-

Question

Hydrogen peroxide in aqueous solution decomposes on warming to give oxygen according to the equation

$2 H_{2} O_{2} (aq) \to 2 H_{2} O (ℓ) + O_{2} (g)$

Under conditions where 1 mole of gas occupies $24 dm^{3} .100 cm^{3}$ of XM solution of $H_{2} O_{2}$ produces $3 dm^{3}$ of $O_{2}$ . Thus X is :-

TestHub · Accepted Answer

2 H 2 ​ O 2 ( aq. ) ​ → 2 H 2 ​ O ( ℓ ) ​ + O 2 ( g ) ​ moles of H 2 ​ O 2 ​ = 0.1 × xM moles of O 2 ​ we get → 2 0.1 × xM ​ volume of O 2 ​ → 3 = 2 0.1 × 2 × 24 ​ x = 2.5

Chemistry - Stoichiometry Question with Solution | TestHub

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