Chemistry - Redox Reactions Question with Solution | TestHub

ChemistryRedox ReactionsMiscellaneous/MixedEasy2 minPYQ_2020

ChemistryEasynumerical

Calculate the amount of calcium oxide (in grams) required when it reacts with 852 g of P₄O₁₀.

Answer:

1008.00

Solution:

$6 CaO + P_{4} O_{10} ⟶ 2 {Ca}_{3} {({PO}_{4})}_{2}$
1 Mole P₄O₁₀= 284 g/mole
Moles of P₄O₁₀= $\frac{852}{284}$ = 3 moles
Moles of CaO = 18 moles
Mass of CaO = 18 x 56 = 1008 g

Stream:NTA_ABHYASSubject:ChemistryTopic:Redox ReactionsSubtopic:Miscellaneous/Mixed

⏱ 2mℹ️ Source: PYQ_2020

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