Chemistry - Stoichiometry Question with Solution | TestHub

ChemistryStoichiometryBasic Methods of Calculations (POAC, LR)Medium2 minQB

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For the reaction:

$2 A + 3 B + 5 C ⟶ 3 D$

Initially, if 2 moles of A, 4 moles of B, and 6 moles of C are taken, with a 25% yield, the moles of D that can be produced are:

Answer:

Solution:

$2 mole A = limiting reagent 2 A + 4 mole 3 B + 6 mole 5 C \to 3 D$

Theoretical yield of $D = \frac{3}{2} \times 2 = 3$ mole

$25 = \frac{x}{3} \times 100$

Actual yield $(x) = 0.75$ mole

Stream:JEESubject:ChemistryTopic:StoichiometrySubtopic:Basic Methods of Calculations (POAC, LR)

⏱ 2mℹ️ Source: QB

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