If the weight ratio of C and O 2 present is 1 : 2 and both of reactants comple | TestHub

Passage / Comprehension

We know that balancing a chemical equation is entirely based on the law of conservation of mass. However, the concept of the Principle of Atom Conservation (POAC) can also be related to the law of conservation of mass in a chemical reaction. Thus, POAC can also act as a technique for balancing a chemical equation.

For example, consider the reaction: $2 A B_{3} \to A B + C_{2}$ .

On applying POAC for B and C, and relating the three equations, we get:

$\frac{n _{A B C_{3}}}{2} = \frac{n _{A B}}{2} = \frac{n _{C_{2}}}{3}$

where $n_{x}$ represents the number of moles of X.

Thus, the coefficients of ABC₃, AB, and C₂ in the balanced chemical equation will be 2, 2, and 3, respectively. The balanced chemical equation can be represented as:

$A B C_{3} \to A B + 3 C_{2}$

Now, answer the following questions:

If the weight ratio of C and $O_{2}$ present is $1 : 2$ and both of reactants completely consume and form CO and $CO_{2}$ and we will obtain a gasous mixture of CO and $CO_{2}$ . What would be the weight ratio of CO and $CO_{2}$ in mixture.

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Answer:

Solution:

Given the weight ratio of C and O₂ = 1 : 2.

Let C = $12 x$ g and O₂ = $24 x$ g, which means oxygen atoms = $24 x$ g.

If $x$ mole C forms CO and CO₂, using POAC:

The CO + CO₂ mixture contains total oxygen = $24 x$ .

Solving the atom balance gives moles of CO : CO₂ = 1 : 1.

Mass ratio:

$CO : C O_{2} = (1 \times 28) : (1 \times 44) = 7 : 11$

Chemistry - Stoichiometry Question with Solution | TestHub

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