Chemistry - Stoichiometry Question with Solution | TestHub

ChemistryStoichiometryProblems Based on Mixtures, Percentage PurityMedium2 minQB

ChemistryMediumnumerical

Amount of CaO is required to neutralise 852 g of $P_{4} O_{10}$ completely is 'w' grams.

(Given: GAW of O=16g, Ca=40g, P=31g)

Answer:

10.08

Solution:

$6 CaO + P_{4} O_{10} \to 2 Ca_{3} (PO_{4})_{2}$

$Wt of CaO = \frac{336 \times 852}{284} = 1008 g, \frac{W}{100} = \frac{1008}{100} = 10.08$

Stream:JEESubject:ChemistryTopic:StoichiometrySubtopic:Problems Based on Mixtures, Percentage Purity

⏱ 2mℹ️ Source: QB

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