Chemistry - Stoichiometry Question with Solution | TestHub

ChemistryStoichiometryBasic Methods of Calculations (POAC, LR)Medium2 minQB

ChemistryMediuminteger

Consider the following reaction:

$3 P b C l_{2} + 2 (N H_{4})_{3} P O_{4} \to P b_{3} (P O_{4})_{2} + 6 N H_{4} Cl$

If 72 mmol of PbCl₂ is mixed with 50 mmol of (NH₄)₃PO₄, then the amount of Pb₃(PO₄)₂ formed is …… mmol. (nearest integer)

Answer:

Solution:

Limiting Reagent is $PbCl_{2}$

mmol of $Pb_{3} (PO_{4})_{2}$ formed

$= \frac{mmol of PbCl _{2} reacted}{3}$ $= 24 mmol$

Stream:JEESubject:ChemistryTopic:StoichiometrySubtopic:Basic Methods of Calculations (POAC, LR)

⏱ 2mℹ️ Source: QB

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