Chemistry - Stoichiometry Question with Solution | TestHub

Question Explanation: The problem requires calculating the total moles of KCl produced across three sequential reactions by accounting for stoichiometric ratios, initial reagent amounts, and specific percentage yields at each step.

Concept: Sequential Reaction Stoichiometry with Yield: In a series of reactions, the actual amount of product from one step becomes the maximum possible reactant for the next, with the final total being the sum of the product generated at every stage.

Solution:

${}^{\mathrm{n}}{\mathrm{Cl}}_2=\frac{112}{22.4}=5$

${\mathrm{n}}_{\mathrm{KOH}}=1\times 10=10$

${\mathrm{Cl}}_2+\mathrm{KOH}\stackrel{60\%}{\to }\mathrm{KCl}+\mathrm{KClO}+{\mathrm{H}}_2\mathrm{O}$

$5105\times 0.65\times 0.6$

$=3=3$

$\mathrm{KClO}\stackrel{50\%}{\to }2\mathrm{KCl}+{\mathrm{KClO}}_3$

$3\frac{2}{3}\times 3\times 0.5\frac{1}{3}\times 3\times 0.5$

$=1=0.5$

${\mathrm{KClO}}_3\stackrel{80\%}{\to }2{\mathrm{KClO}}_4+\mathrm{KCl}$

$\mathrm{0.50.8}\times \frac{0.5}{4}=0.1$

${\left(n_{\mathrm{KCI}}\right)}_{\text{total }}=3+1+0.1=4.1$ moles $=4$ moles .

Final Answer : 4