Chemistry - Stoichiometry Question with Solution | TestHub

Moles of ${\mathrm{HNO}}_3$ obtained is half of moles of ${\mathrm{NH}}_3$ used if ${\mathrm{HNO}}_2$ is not used to produce ${\mathrm{HNO}}_3$ by reaction (IV).

$16.67\%$ more ${\mathrm{HNO}}_3$ will be produced if ${\mathrm{HNO}}_2$ is used to produce ${\mathrm{HNO}}_3$ by reaction (IV) than if ${\mathrm{HNO}}_2$ is not used to produce ${\mathrm{HNO}}_3$ by reaction(IV).

If ${\mathrm{HNO}}_2$ is used to produce ${\mathrm{HNO}}_3$, then $\frac{1}{4}$ th of total ${\mathrm{HNO}}_3$ is produced by reaction(IV).

Moles of NO produced in reaction (IV) is 50% of moles of total ${\mathrm{HNO}}_3$ produced.