If p → Total number of stereoisomers in compound I
q = number of configurational stereoisomers of II
Then value of (p + q) is :

Question

If p → Total number of stereoisomers in compound I q = number of configurational stereoisomers of II Then value of (p + q) is :

TestHub · Accepted Answer

I has two side-chain stereocentres. Cis and trans ring arrangements each give RR, SS and RS (= SR), so p = 3 + 3 = 6. II is CD₃–CH(OH)–CD₃: the two CD₃ groups are identical, so it has no stereocentre and q = 1. Thus p + q = 7. Ring flips and rotamers are not counted as configurations.

Chemistry - STEREO ISOMERISM Question with Solution | TestHub

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