Chemistry - STEREO ISOMERISM Question with Solution | TestHub

1-Phenyl-2-butene, C₆H₅CH₂-CH=CH-CH₃ : each double-bond carbon carries two different groups (H and CH₂C₆H₅ on one, H and CH₃ on the other), so it exists as E and Z isomers.

3-Phenyl-1-butene and 2-phenyl-1-butene contain a terminal =CH₂ group, and 1,1-diphenyl-1-propene carries two identical phenyl groups on one alkene carbon, so none of them can show geometrical isomerism.

Ans. 1-Phenyl-2-butene