Chemistry - Solid State Question with Solution | TestHub

ChemistrySolid StateCubic CrystalsMedium2 minQB

ChemistryMediuminteger

BA crystallizes in CsCl type structure and KCl in NaCl type structure. Edge-length of unit cell of KCl is twice that of BA and molecular weight of BA is twice that of KCl . Calculate ratio of density of BA to that of KCl .

Answer:

Solution:

$d = \frac{Z \times \frac{M _{W}}{N _{A}}}{a ^{3}}$

$\frac{d _{CsCl}}{d _{KCl}} = \frac{1}{4} \times \frac{2}{1} \times (\frac{2}{1})^{3} = 4$

Stream:JEESubject:ChemistryTopic:Solid StateSubtopic:Cubic Crystals

⏱ 2mℹ️ Source: QB

Doubts & Discussion

Loading discussions...