Chemistry - Solid State Question with Solution | TestHub

ChemistrySolid StateGeneralEasy2 minPYQ_2020

ChemistryEasynumerical

Calculate the density (in $k g m^{- 3}$ ) of potassium hving a $b c c$ structure with nearest neighbour distance of $4.52 Å .$ (Given atomic weight of potassium is 39)

Answer:

910.00

Solution:

For bcc, $d = \frac{\sqrt{3}}{2} a$

Or $a = \frac{2 d}{\sqrt{3}} = \frac{2 \times 4.52}{1.732} = 5.219 A^{\circ} = 522 p m$

$ρ = \frac{Z \times M}{a^{3} \times N_{0} \times 1 0^{- 30}}$

$= \frac{2 \times 39}{(522)^{3} \times (6.023 \times 1 0^{23}) \times 1 0^{- 30}} = 0.91 g / c m^{3} = 910 k g m^{- 3}$

Stream:JEESubject:ChemistryTopic:Solid StateSubtopic:General

⏱ 2mℹ️ Source: PYQ_2020

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