Chemistry - Solid State Question with Solution | TestHub

Edge length of the unit cell, $a=300\text{ pm}=3\times 10^{-8}\text{ cm}$

Volume of the unit cell, $V=a^3=(3\times 10^{-8}\text{ cm}{)}^3=27\times 10^{-24}{\text{ cm}}^3$

Density of the metal, $d=7.2{\text{ g cm}}^{-3}$

Mass of all atoms in the unit cell is equal to the mass of the unit cell.

Mass of unit cell $=V\times d$

Mass $=27\times 10^{-24}{\text{ cm}}^3\times 7.2{\text{ g cm}}^{-3}=194.4\times 10^{-24}\text{ g}=1.944\times 10^{-22}\text{ g}$

Answer: $1.944\times 10^{-22}$ g