Chemistry - Solid State Question with Solution | TestHub

Packing Fraction for cubic close packing is$$\frac{{\text{N}}_{\text{atoms}}\times {\text{V}}_{\text{atom}}}{{\text{V}}_{\text{unitcell}}}=\frac{6.\frac{4}{3}{\text{πr}}^3}{\frac{3{(3)}^{\frac{1}{2}}}{2}{(2\text{r})}^2{(2/3)}^{\frac{1}{2}}.4\text{r}}=0.74\Rightarrow 74\%$$