Chemistry - Solid State Question with Solution | TestHub

Edge length of the unit cell, $a=200\text{ pm}=2\times 10^{-8}\text{ cm}$

Volume of the unit cell, $V=a^3=(2\times 10^{-8}{)}^3=8\times 10^{-24}{\text{ cm}}^3$

For a face-centered cubic (fcc) structure, the packing efficiency is $74\%$.

Volume occupied by particles in the unit cell = $0.74\times V$

$=0.74\times 8\times 10^{-24}{\text{ cm}}^3$

$=5.92\times 10^{-24}{\text{ cm}}^3$

Answer: $5.92\times 10^{-24}{\text{cm}}^3$