Chemistry - Solid State Question with Solution | TestHub

Mass of one unit-cell$\text{(m)}$= volume$\times$density

$\text{=}{\text{a}}^{\text{3}}\text{×}\text{d}\text{=}{\text{a}}^{\text{3}}\text{×}\frac{\text{MZ}}{{\text{N}}_{\text{0}}{\text{a}}^{\text{3}}}\text{=}\frac{\text{MZ}}{{\text{N}}_{\text{0}}}$

$\text{m}\text{=}\frac{\text{58}\text{.5}\text{×}\text{4}}{\text{6}\text{.02}\text{×}{\text{10}}^{\text{23}}}\text{ g}$

$\therefore$Number of unit cells in$\text{1}\text{g}\text{=}\frac{\text{1}}{\text{m}}$

$=\frac{{6.02\times 10}^{23}}{58.5\times 4}$

$=2.57\times {10}^{21}$