Chemistry - Solid State Question with Solution | TestHub

Number of atoms in $0.6$ mol of the compound is $N=0.6\times 6.022\times 10^{23}=3.6132\times 10^{23}$.

In a close-packed structure, the number of octahedral voids is equal to the number of atoms, $N$.

The number of tetrahedral voids is twice the number of atoms, $2N$.

Total number of voids $=N+2N=3N$.

Total number of voids $=3\times 3.6132\times 10^{23}=10.8396\times 10^{23}=1.084\times 10^{24}$.

Answer: $1.084\times 10^{24}$