Chemistry - Solid State Question with Solution | TestHub

Dipole-induced dipole interactions occur between a polar molecule (which has a permanent dipole moment) and a non-polar molecule (which lacks a permanent dipole moment).

${\mathrm{NH}}_3$ is a polar molecule, while ${\mathrm{C}}_6{\mathrm{H}}_6$ (benzene) is a non-polar molecule. Therefore, the interaction between them is dipole-induced dipole.

$\mathrm{NaCl}$ and ${\mathrm{H}}_2\mathrm{O}$ exhibit ion-dipole interactions.

${\mathrm{CH}}_4$ and ${\mathrm{C}}_2{\mathrm{H}}_6$ are both non-polar, so they exhibit London dispersion forces (induced dipole-induced dipole).

$\mathrm{HF}$ and ${\mathrm{H}}_2\mathrm{O}$ are both polar and exhibit hydrogen bonding (a strong type of dipole-dipole interaction).

Answer: ${\mathrm{NH}}_3+{\mathrm{C}}_6{\mathrm{H}}_6$