Chemistry - Solid State Question with Solution | TestHub
ChemistrySolid StateMiscellaneous/MixedHard2 minPYQ_2011
ChemistryHardnumerical
The number of hexagonal faces that are present in a truncated octahedron is
Answer:
8.00
Solution:
The truncated octahedron is the 14 -faced Archimedean solid, with 14 total faces. 6 squares and 8 regular hexagons. The truncated octahedron is formed by removing the six right square pyramids one from each point of a regular octahedron as:
Stream:JEE_ADVSubject:ChemistryTopic:Solid StateSubtopic:Miscellaneous/Mixed
⏱ 2mℹ️ Source: PYQ_2011
Doubts & Discussion
Loading discussions...