Chemistry - Solid State Question with Solution | TestHub

For bcc unit cell, $r=\frac{\sqrt{3}}{4}\mathrm{a}$ $\begin{array}{rl}\therefore \mathrm{a}=\frac{4\mathrm{r}}{\sqrt{3}}=\frac{4\times 227}{1.73}& =524.85\mathrm{pm}\\ & =524.85\times 10^{-10}\mathrm{cm}\\ & =5.24\times 10^{-8}\mathrm{cm}\end{array}$