Chemistry - Solid State Question with Solution | TestHub

Number of NaCl unit in one gram$=\frac{1}{\text{58.5}}\times \text{6.023}\times \text{1}{\text{0}}^{\text{23}}=\text{1.029}\times \text{1}{\text{0}}^{\text{22}}$

A unit cell contains$4\hspace{0.33em}\mathrm{N}{\mathrm{a}}^{+}$ion and$4\hspace{0.33em}\mathrm{C}{\mathrm{l}}^{-}$ions

Unit cell$=\frac{\text{1.029}\times \text{1}{\text{0}}^{\text{22}}}{4}=\text{2.57}\times \text{1}{\text{0}}^{\text{21}}$unit cell