Semiconducting, non-stoichiometric nickel(II) oxide can be prepared by the reaction of stoichiometric compound with oxygen gas. 'V' ml of oxygen gas at 27°C and 2.4 atm is used for convertin

Question

Semiconducting, non-stoichiometric nickel(II) oxide can be prepared by the reaction of stoichiometric compound with oxygen gas. 'V' ml of oxygen gas at 27°C and 2.4 atm is used for converting 72.459 gm of NiO to the appropriate amount of $Ni_{0.97} O_{1.00}$ . The value of ' V ' is ?

(Molar mass of Ni is 58.7, R = 0.08 L-atm/K-mole)

TestHub · Accepted Answer

To convert 72.459 g of NiO to Ni₀.₉₇O₁.₀₀, first find the moles of NiO.

Moles of NiO = $72.459 g / (58.7 + 16) g / m o l = 0.9699 m o l$ .

The reaction is $0.97 N i O + 0.015 O_{2} \to N i_{0.97} O_{1.00}$ .

Moles of O₂ needed = $0.9699 m o lN i O \times (0.015 m o l O_{2} /0.97 m o lN i O) = 0.015 m o l O_{2}$ .

Using $P V = n RT$ : $V = (0.015 m o l \times 0.08 L - a t m / K - m o l \times 300 K) /2.4 a t m = 0.15 L = 150 m L$ .

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