Chemistry - Solid State Question with Solution | TestHub

$\begin{array}{rl}\text{ Vol. of unit cell }& =(100\mathrm{pm}{)}^3={\left(100\times 10^{-10}\mathrm{cm}\right)}^3\\ & =10^{-24}{\mathrm{cm}}^3\end{array}$ Vol. of $100\mathrm{g}$ of an element $=\frac{\text{ Mass }}{\text{ Density }}=\frac{100\mathrm{g}}{10\mathrm{g}{\mathrm{cm}}^{-3}}=10{\mathrm{cm}}^3$ No. of unit cells in $100\mathrm{g}$ of an element $=\frac{\text{ Total volume }}{\text{ Volume of one unit cell }}$ $=\frac{10{\mathrm{cm}}^3}{10^{-24}{\mathrm{cm}}^3}=1\times 10^{25}$ unit cells.