In a compound oxide ion have ccp arrangement, cations A are present in 1 8 of the tetrahedral voids and cations B occupy 1 2 of the octahedral voids. What are the formula of the compound?

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TestHub · Accepted Answer

Oxide ions are forming the lattice
Effective number of oxide ions $= 4 (c c p)$
$∴$ Tetrahedral voids $= 2 \times 4 = 8$
And effective number of A atom $= \frac{1}{8} \times 8 = 1$
Number of octahedral voids $= 4$
Effective number of B atom $= \frac{1}{2} \times 4 = 2$
$∴$ Molecular formulae $= A B_{2} O_{4}$

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