Copper has face-centered cubic (fcc) lattice with interatomic spacing equal to 2.54 A ˚ . The value of lattice constant for this lattice is

Interatomic spacing for a fcc lattice r = [ ( 2 a ) 2 + ( 2 a ) 2 + ( 0 ) 2 ] 1/2 = 2 a a being lattice constant. ∴ a = 2 r = 2 × 2.54 = 3.59 A ˚ NOTE : Interatomic spacing is just the nearest neighbours distance.

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Chemistry - Solid State Question with Solution | TestHub

ChemistrySolid StateCubic CrystalsMedium2 minPYQ_2007

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Copper has face-centered cubic (fcc) lattice with interatomic spacing equal to $2.54 \overset{˚}{A}$ . The value of lattice constant for this lattice is

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Interatomic spacing for a fcc lattice $r = [(\frac{a}{2})^{2} + (\frac{a}{2})^{2} + (0)^{2}]^{1/2} = \frac{a}{2}$ a being lattice constant. $∴ a = 2 r = 2 \times 2.54 = 3.59 \overset{˚}{A}$ NOTE : Interatomic spacing is just the nearest neighbours distance.

Stream:JIPMERSubject:ChemistryTopic:Solid StateSubtopic:Cubic Crystals

⏱ 2mℹ️ Source: PYQ_2007

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