In a structure of mixed oxide, oxide ions are in CCP. One fifth of tetrahedral voids are occupied by divalent ion ( A 2 + ) while half of the octahedral voids are occupied by trivalent ion ( B 3 + ) ,

Question

In a structure of mixed oxide, oxide ions are in CCP. One fifth of tetrahedral voids are occupied by divalent ion ( A 2 + ) while half of the octahedral voids are occupied by trivalent ion ( B 3 + ) , the formula is :-

TestHub · Accepted Answer

Number of O²⁻ ions in the unit cell = 4 N u mb ero f A 2 + i o n = 5 1 ​ × ( t e t r ah e d r a l v o i d s ) = 5 1 ​ × ( 4 × 2 ) = 5 8 ​ Number of B³⁺ ions = 2 1 ​ × ( oc t ah e d r a l v o i d s ) = 2 1 ​ × 4 = 2 . Thus we have: A 5 8 ​ 8 4 ​ : : : : ​ B 2 10 5 ​ : : : : ​ O 4 20 10 ​ The formula of the compound is A₄B₅O₁₀.

Chemistry - Solid State Question with Solution | TestHub

Options:

Doubts & Discussion