Chemistry - Salt Analysis Question with Solution | TestHub

Explain Question:

Calculate the difference between atomicity and MoO₃ units.

Concept:

Arsenic Qualitative Analysis and Magnesia Mixture.

Solution:

Compound A (As³⁺) forms yellow B (As₂S₃), which oxidizes to C (H₃AsO₄).

C reacts with ammonium molybdate to form D ($(N{H}_4{)}_3[AsM{o}_{12}{O}_{40}]\cdot 6H_{2}O$), containing 12 MoO₃ units.

C reacts with magnesia mixture to form E (MgNH₄AsO₄), excluding water of crystallization as specified.

Calculation:

1. Units of MoO₃ in D: $x=12$

2. Atomicity of E (MgNH₄AsO₄): $1(Mg)+1(N)+4(H)+1(As)+4(O)=11$.

Thus, $y=11$.

3. Value: $y-x=11-12=-1$.

4. Final Answer: $(-1)$