Find the number of acidic radicals that decolorize an acidic solution of $KMnO_{4}$ .
SO₃²⁻, C₂O₄²⁻, Br⁻, I⁻, S₂O₃²⁻, NO₂⁻

Question

Find the number of acidic radicals that decolorize an acidic solution of KMnO 4 ​ . SO₃²⁻, C₂O₄²⁻, Br⁻, I⁻, S₂O₃²⁻, NO₂⁻

TestHub · Accepted Answer

In acidic medium, KMnO₄ is a strong oxidizing agent and is decolorized by reducing anions.
Among the given ions, SO₃²⁻, C₂O₄²⁻, Br⁻, I⁻, S₂O₃²⁻, and NO₂⁻ all reduce acidified KMnO₄ to Mn²⁺, causing the purple color to disappear.
Hence, all six acidic radicals decolorize acidic KMnO₄ solution.

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JEE Advanced 2027 (Class 12)