Find the number of anionic radicals which are oxidized by an acidic solution of $KMnO_{4}$ .

SO₃²⁻, C₂O₄²⁻, Br⁻, I⁻, S₂O₃²⁻, NO₂⁻, F⁻

Question

Find the number of anionic radicals which are oxidized by an acidic solution of KMnO 4 ​ . SO₃²⁻, C₂O₄²⁻, Br⁻, I⁻, S₂O₃²⁻, NO₂⁻, F⁻

TestHub · Accepted Answer

Acidified KMnO₄ is a strong oxidizing agent and oxidizes reducing anions. Among the given radicals, SO₃²⁻, C₂O₄²⁻, Br⁻, I⁻, S₂O₃²⁻, and NO₂⁻ are oxidized by acidic KMnO₄. F⁻ can never be oxidized by any oxidizing agent. Hence, the number of anionic radicals oxidized = 6 .

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