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ChemistrySalt AnalysisTEST OF ANIONS CLASS A-SUBGROUP IIMedium2 minPYQ_2024
ChemistryMediumstatement

Oxidation state of Fe(Iron) in complex formed in Brown ring test.

Answer:
1
Solution:

The chemical test called a brown ring test is conducted to find out the presence of Nitrate ions in any solution, in which the solutions form a brown ring in the test tube.

The above test is also called the brown ring test, in which the brown ring complex compound is formulated as [Fe(H2O)5NO]SO4. 

Here the oxidation state of Iron in the complex, can be found as:

We can assume that the oxidation state of Iron metal is x.

Here the oxidation state of the Sulphate ion is 2, the oxidation state of water is zero and the oxidation state of Nitroso NO is +1.Hence, the oxidation state of Iron can be calculated as:
x+(+1)+5(0)=+2x=+1

Stream:JEESubject:ChemistryTopic:Salt AnalysisSubtopic:TEST OF ANIONS CLASS A-SUBGROUP II
2mℹ️ Source: PYQ_2024

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