Chemistry - Salt Analysis Question with Solution | TestHub

Based on the chemical reactions for the $P{b}^{2+}$ ion:

A is $PbC{l}_2$ (white precipitate), formed by the reaction of $P{b}^{2+}$ with dilute $HCl$.

In the presence of excess $KCl$ and $H_{2}S$, lead forms the intermediate chlorosulphide precipitate $P{b}_{2}SC{l}_2$ (E).

Upon dilution, E decomposes to yield the black precipitate $PbS$ (D) and white $PbC{l}_2$ (A).

Therefore, precipitates D and E are $PbS$ and $P{b}_{2}SC{l}_2$ respectively, making (C) the correct option.