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Chemistry - Salt Analysis Question with Solution | TestHub

ChemistrySalt AnalysisTEST OF CATIONS, Group 3, 4, 5, 6, 0Medium2 minPYQ_2023

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A solution of ${FeCl}_{3}$ when treated with $K_{4} [Fe (CN)_{6}]$ gives a prussian blue precipitate due to the formation of

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Answer:

Solution:

Addition of ${FeCl}_{3}$ to $K_{4} [Fe {(CN)}_{6}]$ in dilute and cold solution gives a solution, prussian blue solution ${Fe}_{4} {[Fe {(CN)}_{6}]}_{3}$ .

The reaction is as follows:

$4 {FeCl}_{3} + 3 K_{4} [Fe (CN)_{6}] \to {Fe}_{4} [Fe (CN)_{6}]_{3} + 12 KCl$

Stream:JEESubject:ChemistryTopic:Salt AnalysisSubtopic:TEST OF CATIONS, Group 3, 4, 5, 6, 0

⏱ 2mℹ️ Source: PYQ_2023

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