Chemistry - Salt Analysis Question with Solution | TestHub

${\text{Li}}_2\text{O}+2\text{KCl}\to 2\text{LiCl}+{\text{K}}_2\text{O}$is incorrect since,$\mathrm{KCl}$is less reactive than$\mathrm{LiCl}$and will not form$\mathrm{LiCl}$.

${\left[\mathrm{Mg}{\left({\mathrm{H}}_2\mathrm{O}\right)}_6\right]}^{2+}+{\left(\mathrm{EDTA}\right)}^{4-}\stackrel{\mathrm{excess} NaOH}{\to }{\left[\mathrm{Mg}\left(\mathrm{EDTA}\right)\right]}^{2+}+6{\mathrm{H}}_2\mathrm{O}$is incorrect since, the charge on the complex will be$-2$, not$+2$.

${\mathrm{CuSO}}_4+4\mathrm{KCN}\to {\mathrm{K}}_2\left[\mathrm{Cu}{\left(\mathrm{CN}\right)}_4\right]+{\mathrm{K}}_2{\mathrm{SO}}_4$is incorrect since, the final complex formed is${\mathrm{K}}_3\left[\mathrm{Cu}{\left(\mathrm{CN}\right)}_4\right]$, not${\mathrm{K}}_2\left[\mathrm{Cu}{\left(\mathrm{CN}\right)}_4\right]$.