Chemistry - Redox Reactions Question with Solution | TestHub
ChemistryRedox ReactionsDetermination of Oxidation StateMedium2 minQB
ChemistryMediumsingle choice
A certain amount of a reducing agent reduces mole of and mole of in different reactions in acidic medium. If the changes in oxidation states of reducing agent in the reactions are in 2:1 ratio, respectively, then the ratio of and is
Options:
Answer:
B
Solution:
: Mn +7 +2 takes 5 ; : 2Cr +6 +3 takes 6 . With reductant n-factors = 2:1 and the same amount of reductant: = , = . So x/y = () = (6 × 2)/(5 × 1) = 12/5. Hence (b).
Stream:JEESubject:ChemistryTopic:Redox ReactionsSubtopic:Determination of Oxidation State
⏱ 2mℹ️ Source: QB
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