The table below gives the results of three titrations carried out with 0.200 M HCl to determine the molarity of a given NaOH solution using phenolphthalein as indicator. NaOH was taken in the burette

Question

The table below gives the results of three titrations carried out with 0.200 M HCl to determine the molarity of a given NaOH solution using phenolphthalein as indicator. NaOH was taken in the burette and HCl was taken in a conical flask for the titrations

The actual molarity of the prepared NaOH solution was 0.220 mol dm^-3. Which among the following could be the reason for the wrong value obtained in titration III?

Options:

Answer:

C

Solution:

$[O H^{-}] = \frac{n_{O H^{-}}}{V_{O H^{-}}} = \frac{n_{a c i d}}{V_{N a O H}} = \frac{[H C l] V_{H C l}}{V_{N a O H}} = 0.21 M < 0.220$

TestHub · Accepted Answer

O H - = n O H - V O H - = n a c i d V N a O H = H C l V H C l V N a O H = 0.21 M < 0.220

Chemistry - Redox Reactions Question with Solution | TestHub

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