A metal (M) forms a hydrated sulphate, isomorphous with FeS O 4 ⋅ 7 H 2 O . If the sulphate contains about 21% metal, by weight, which of the following is/are correct for the metal?

Isomorphous with FeS O 4 ⋅ 7 H 2 O means MS O 4 ⋅ 7 H 2 O with M bivalent. Then A/(A + 96 + 126) = 0.21 → A = 0.21 x 222/0.79 = 59.0, which matches cobalt (A = 59). E = 59/2 = 29.5, the metal is bivalent, and it is cobalt - all four statements hold.

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Chemistry - Redox Reactions Question with Solution | TestHub

ChemistryRedox ReactionsProblem involving Equivalent ConceptMedium2 minQB

ChemistryMediummultiple choice

A metal (M) forms a hydrated sulphate, isomorphous with $FeS O_{4} \cdot 7 H_{2} O$ . If the sulphate contains about 21% metal, by weight, which of the following is/are correct for the metal?

Options:(select one or more)

Answer:

A, B, C, D

Solution:

Isomorphous with $FeS O_{4} \cdot 7 H_{2} O$ means $MS O_{4} \cdot 7 H_{2} O$ with M bivalent. Then A/(A + 96 + 126) = 0.21 $\to$ A = 0.21 $x$ 222/0.79 = 59.0, which matches cobalt (A = 59). E = 59/2 = 29.5, the metal is bivalent, and it is cobalt - all four statements hold.

Stream:JEESubject:ChemistryTopic:Redox ReactionsSubtopic:Problem involving Equivalent Concept

⏱ 2mℹ️ Source: QB

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