Chemistry - Redox Reactions Question with Solution | TestHub

The same mass of oxalic acid supplies the same g-eq (say 1 eq) in each experiment. $\mathrm{KMn}{\mathrm{O}}_4$ ($n$ = 5): 0.2 mol = 31.6 g; ${\mathrm{K}}_2\mathrm{C}{\mathrm{r}}_2{\mathrm{O}}_7$ ($n$ = 6): 1/6 mol = 49 g. So the mass of ${\mathrm{K}}_2\mathrm{C}{\mathrm{r}}_2{\mathrm{O}}_7$ is greater (a true) while its moles (0.167) are fewer than those of $\mathrm{KMn}{\mathrm{O}}_4$ (0.2) (b true). All the $\mathrm{C}{\mathrm{O}}_2$ comes from the same oxalic acid, so equal g-eq give equal masses of $\mathrm{C}{\mathrm{O}}_2$ (c true). Equal volumes reacting completely means equal g-eq, i.e. equal normalities: $5{\mathrm{M}}_1$ = $6{\mathrm{M}}_2$, so $\mathrm{M}(\mathrm{KMn}{\mathrm{O}}_4):\mathrm{M}({\mathrm{K}}_2\mathrm{C}{\mathrm{r}}_2{\mathrm{O}}_7)$ = 6:5 (d true). All four.