In the redox reaction: C r O 5 + H 2 S O 4 → C r 2 ( S O 4 ) 3 + H 2 O + O 2

Question

In the redox reaction: C r O 5 ​ + H 2 ​ S O 4 ​ → C r 2 ​ ( S O 4 ​ ) 3 ​ + H 2 ​ O + O 2 ​

TestHub · Accepted Answer

Oxidation States: In CrO₅ (butterfly structure), Cr is in the +6 state, four O atoms are peroxides (-1), and one is an oxide (-2).

Chromium Reduction: Cr is reduced from +6 to +3 in Cr₂(SO₄)₃, making (A) correct.

Oxygen Redox Ratio: In the balanced reaction $4 C r O_{5} + 6 H_{2} S O_{4} \to 2 C r_{2} (S O_{4})_{3} + 6 H_{2} O + 7 O_{2}$ , 14 moles of O¹⁻ are oxidized to O₂, and 2 moles of O¹⁻ are reduced to O²⁻ in H₂O.

Mole Ratio & Reaction Type: This gives an oxidation-to-reduction mole ratio of $14 : 2 = 7 : 1$ , making (C) correct. It is classified as a comproportionation/intra-molecular redox rather than a standard disproportionation reaction, making (D) correct.

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