Chemistry - Redox Reactions Question with Solution | TestHub

$\mathrm{C}{\mathrm{H}}_3\mathrm{COOH}$ + $\mathrm{C}{\mathrm{l}}_2$ $\to$ $\mathrm{C}{\mathrm{H}}_2\mathrm{ClCOOH}$ + $\mathrm{HCl}$: one C-H bond becomes C-Cl, so the acid loses 2 ${\mathrm{e}}^{-}$ per mole (one $\mathrm{C}{\mathrm{l}}_2$ accepts 2 ${\mathrm{e}}^{-}$). $n$ = 2, Eq wt = 60/2 = 30. Hence (c).