Chemistry - Redox Reactions Question with Solution | TestHub

ChemistryRedox ReactionsEquivalent Weight and n-factorMedium2 minQB

ChemistryMediumsingle choice

Passage / Comprehension

For the reaction: MnBr₂ + PbO₂ + HNO₃ $\to$ HMnO₄ + Pb(BrO₃)₂ + Pb(NO₃)₂ + H₂O (Atomic masses: Mn = 55, Br = 80, Pb = 208)

The equivalent weight of HNO₃ is

Options:

Answer:

Solution:

Balancing the redox: 2 MnBr₂ + 17 PbO₂ + 30 HNO₃ $\to$ 2 HMnO₄ + 2 Pb(BrO₃)₂ + 15 Pb(NO₃)₂ + 14 H₂O. Equivalents of oxidant = 17 × 2 = 34, and 30 mol HNO₃ supply these equivalents in this reaction, so n-factor of HNO₃ here = 34/30. E = 63 × 30/34 = 55.6, matching (b).

Stream:JEESubject:ChemistryTopic:Redox ReactionsSubtopic:Equivalent Weight and n-factor

⏱ 2mℹ️ Source: QB

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