Chemistry - Redox Reactions Question with Solution | TestHub
ChemistryRedox ReactionsProblem involving Equivalent ConceptEasy2 minQB
ChemistryEasysingle choice
A small amount of CaCO₃ completely neutralizes 525 ml of 0.1 N HCl and no acid is left at the end. After converting all calcium chloride to CaSO₄, how much plaster of Paris can be obtained?
Options:
Answer:
D
Solution:
meq HCl = 525 x 0.1 = 52.5 meq, so CaCO₃ = 52.5 meq = 26.25 mmol, giving 26.25 mmol Ca²⁺. Plaster of Paris is CaSO₄·1/2H₂O (molar mass 145): mass = 26.25 x 145 mg = 3.81 g, option (d).
Stream:JEESubject:ChemistryTopic:Redox ReactionsSubtopic:Problem involving Equivalent Concept
⏱ 2mℹ️ Source: QB
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