In the ionic reaction x I O 3 − + y M n 2 + + z H 2 O → p I 2 + q Mn O 4 − + r H + (x, y, z, p, q, r are in the simplest whole number ratio) find the value of (x + y + z + p + q + r) till you

Question

In the ionic reaction x I O 3 − ​ + y M n 2 + + z H 2 ​ O → p I 2 ​ + q Mn O 4 − ​ + r H + (x, y, z, p, q, r are in the simplest whole number ratio) find the value of (x + y + z + p + q + r) till you get a single digit answer.

TestHub · Accepted Answer

I goes from +5 to 0: 5 electrons per I, 10 per $I_{2}$ . Mn goes from +2 to +7: 5 electrons.

Electrons balance at 2 $IO_{3}^{-}$ (10 e) and 2 $Mn^{2 +}$ (10 e): x = 2, y = 2, p = 1, q = 2.

Charge: left = -2 + 4 = +2; right = -2 + r, so r = 4. Hydrogen: 2z = r = 4, so z = 2.

Oxygen check: 6 + 2 = 8 = 4 × 2. Good.

Sum = 2 + 2 + 2 + 1 + 2 + 4 = 13; 1 + 3 = 4.

Answer: 4.

Chemistry - Redox Reactions Question with Solution | TestHub

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