Correct code for True : T and False : F (i) In Symmetrical N 2 O 3 molecules one N − O − N linkage is present (ii) Basicity for H₄P₂O₇ is four. (iii) Oxidation state of 'S' in Caro'

Question

Correct code for True : T and False : F

(i) In Symmetrical $N_{2} O_{3}$ molecules one $N - O - N$ linkage is present

(ii) Basicity for H₄P₂O₇ is four.

(iii) Oxidation state of 'S' in Caro's acid and Marshall's acid is +5.

(iv) Number of P–O–P linkages in H₄P₄O₁₂ is four.

(v) Oxidation state of Cr in K₃CrO₈ is +6.

TestHub · Accepted Answer

Question Explanation: Check the correctness of all given statements using structure, basicity, and oxidation state.

Concept: Oxidation state and structure rules.

Solution:

(i) Symmetrical N₂O₃ has the structure $O = N - O - N = O$ , which has one $N - O - N$ linkage. This statement is True.

(ii) H₄P₂O₇ has 4 ionizable hydrogens, so its basicity is 4. This statement is True.

(iii) For H₂SO₅: $2 (+ 1) + S + 5 (- 2) = 0 \Rightarrow S = + 6$

For H₂S₂O₈:

2 (+ 1) + 2 S + 8 (- 2) = 0 \Rightarrow S = + 6

The given oxidation state of +5 is incorrect. This statement is False.

(iv) H₄P₄O₁₂ is cyclic, with 4 P atoms and 4 P-O-P linkages. This statement is True.

(v) For CrO₅: $3 (+ 1) + C r + 8 (- 2) = 0 \Rightarrow 3 + C r - 16 = 0 \Rightarrow C r = + 13$ (incorrect assumption).

Considering peroxide linkages, the oxidation state of Cr is +5. This statement is False.

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