Chemistry - Redox Reactions Question with Solution | TestHub

ChemistryRedox ReactionsMiscellaneous/MixedEasy2 minPYQ_2020

ChemistryEasysingle choice

Equivalent weight of $K M n O_{4}$ when it is convect into $M n S O_{4}$ is Where M = molar mass of $K M n O_{4}$ .

Options:

Answer:

Solution:

$M n O_{4}^{-} + 5 e^{-} \to M n^{2 +}$

So equivalent weight of $K M n O_{4}$

$= \frac{Molar mass of KMn O_{4} (M)}{No. of mol of electrons gained by 1 mol of KMn O_{4}}$

$= \frac{M}{5}$ .

Stream:NTA_ABHYASSubject:ChemistryTopic:Redox ReactionsSubtopic:Miscellaneous/Mixed

⏱ 2mℹ️ Source: PYQ_2020

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