Chemistry - Redox Reactions Question with Solution | TestHub
ChemistryRedox ReactionsEquivalent Weight and n-factorMedium2 minQB
ChemistryMediumsingle choice
Passage / Comprehension
For the reaction: MnBr₂ + PbO₂ + HNO₃ HMnO₄ + Pb(BrO₃)₂ + Pb(NO₃)₂ + H₂O (Atomic masses: Mn = 55, Br = 80, Pb = 208)
The equivalent weight of MnBr₂ is
Options:
Answer:
C
Solution:
In MnBr₂, Mn²⁺ Mn⁷⁺ (in HMnO₄) loses 5 e⁻ and each Br⁻ Br⁵⁺ (in BrO₃⁻) loses 6 e⁻, so 2 Br lose 12 e⁻. Total n-factor = 5 + 12 = 17. M(MnBr₂) = 55 + 160 = 215. E = 215/17 = 12.65, matching (c).
Stream:JEESubject:ChemistryTopic:Redox ReactionsSubtopic:Equivalent Weight and n-factor
⏱ 2mℹ️ Source: QB
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