Chemistry - Redox Reactions Question with Solution | TestHub

${\mathrm{H}}_2{\mathrm{O}}_2+2\mathrm{KI}\to {\mathrm{I}}_2+2\mathrm{KOH}$

Volume strength of ${\mathrm{H}}_2{\mathrm{O}}_2=\mathrm{M}\times 11.35,\mathrm{M}=1$

Number of milli equivalents of ${\mathrm{H}}_2{\mathrm{O}}_2=100\times 1\times 2=200$

Number of milli equivalents of $\mathrm{KI}=50\times 0.5\times 1=25=$ Number of milli equivalents of ${\mathrm{I}}_2$

Number of milli equivalents of ${\mathrm{H}}_2{\mathrm{O}}_2$ left $=175$

a) Volume strength of ${\mathrm{H}}_2{\mathrm{O}}_2$ left $=11.35\times \frac{175}{150}\times \frac{1}{2}=6.62\mathrm{V}$

b) $500\times \mathrm{M}\times 2=25,\mathrm{M}=0.025$

c) 200 ml pf X has $\frac{25}{500}\times 200$ milli equivalents of $\mathrm{I}2=$ milli equivalents of hypo. $\frac{25}{500}\times 200=50\times \mathrm{M}\times 1;\mathrm{M}=0.2$

d)

${\mathrm{I}}_2+2\mathrm{Na},{\mathrm{S}}_2{\mathrm{O}}_3\to 2\mathrm{NaI}+{\mathrm{Na}}_2{\mathrm{S}}_4{\mathrm{O}}_6$

$$50\times 0.2=10\mathrm{m}\text{ moles }5\mathrm{m}\text{ moles }$$